Y=4x^2-5x+6

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Solution for Y=4x^2-5x+6 equation: 



=4Y^2-5Y+6

We move all terms to the left:

-(4Y^2-5Y+6)=0

We get rid of parentheses

-4Y^2+5Y-6=0

a = -4; b = 5; c = -6;
Δ = b2-4ac
Δ = 52-4·(-4)·(-6)
Δ = -71
Delta is less than zero, so there is no solution for the equation

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